3y^2-0.27=0

Solution for 3y^2-0.27=0 equation:

3y^2-0.27=0

a = 3; b = 0; c = -0.27;
Δ = b2-4ac
Δ = 02-4·3·(-0.27)
Δ = 3.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3.24}}{2*3}=\frac{0-\sqrt{3.24}}{6}
=-\frac{\sqrt{}}{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3.24}}{2*3}=\frac{0+\sqrt{3.24}}{6}
=\frac{\sqrt{}}{6}
$